49x^2+112x+64=25

Solution for 49x^2+112x+64=25 equation:

49x^2+112x+64=25

We move all terms to the left:

49x^2+112x+64-(25)=0

We add all the numbers together, and all the variables

49x^2+112x+39=0

a = 49; b = 112; c = +39;
Δ = b2-4ac
Δ = 1122-4·49·39
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(112)-70}{2*49}=\frac{-182}{98}
=-1+6/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(112)+70}{2*49}=\frac{-42}{98}
=-3/7
$